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Satisfactory factories
Satisfactory factories







satisfactory factories

6 iron plate = 6 * 30 / 20 = 9 iron ingot.uses 1080 iron plate and 2160 screw to produce 180 reinforced iron plate per minute in 36 assembler.uses 1200 iron ingot to produce 4800 screws per minute in 96 constructors.uses 1440 iron ingot to produce 1440 iron rods per minute in 64 constructors.uses 2160 iron ingot to produce 1440 iron plates per minute in 72 constructors.uses 2160 iron ore to produce 2160 iron ingot per minute in 72 smelters.The following are the required production lines:

satisfactory factories

We will be using the basic recipes for each of the materials except for screws where we will be using the cast screw recipe that steps the usual iron rod step. This will mean that we will need to produce much more than 2,160 screw to maximise the output of the advanced iron materials, which are reinforced iron plates, rotors and modular frames. We will design each material output, to either produce at lest 1,440 per minute for the basic materials of iron plates, rods and screws, to feed an industrial storage container at the maximum rate, or whatever rate consumes all of the iron ore on the input (in our case 2,160 per minute). The next step is to design the production lines. 3 miners and 1 power shard each you will be producing the iron materials in the game at quite sufficient rates to do anything in the game. For further scaling you can deliver more iron ore using a transportation network, although with about 3 pure iron ore sources, Mk. Starting with the location, pick somewhere with good access to iron ore, which is the only required input.









Satisfactory factories